In a locked box, there are 3 red balls, 5 blue balls, and 2 green balls. What is the probability of randomly selecting a blue ball and then a green ball without replacement?
Category: Math · Difficulty: expert
Hint: Consider the total balls and the order of selection.
Answer
1/12
Explanation
The probability of choosing a blue ball first is 5/10, and then a green ball is 2/9. Multiply these probabilities for the final answer: (5/10)*(2/9) = 1/12.
This is a expert math riddle — one of the harder riddles here. The answer is 1/12.
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